Friday, January 23, 2009

Design an IP addressing scheme.

Given the IP address block of 192.168.7.0 /24, design an IP addressing scheme that satisfies the
following requirements:
Subnet Number of Hosts
Subnet A 110
Subnet B 54
The 0 subnet is used. No subnet calculators may be used. Create the smallest possible subnets that
satisfy the requirements for hosts. Assign the first usable subnet to Subnet A.
Subnet A
Specification Student Input
Number of bits in the subnet 1
IP mask (binary) 11111111. 11111111. 11111111.10000000
New IP mask (decimal) 255.255.255.128
Maximum number of usable
subnets (including the 0 subnet)
2
Number of usable hosts per
subnet
126
IP subnetwork address 192.168.7.0
First IP host address 192.168.7.1
Last IP host address 192.168.7.126
Subnet B
Specification Student Input
Number of bits in the subnet 2
IP mask (binary) 11111111. 11111111.
11111111.11000000
New IP mask (decimal) 255.255.255.192
Maximum number of usable subnets
(including the 0 subnet)
2
Number of usable hosts per subnet 62
IP network address 192.168.7.128
First IP host address 192.168.7.129
Last IP host address 192.168.7.190
Host computers will use the first usable IP address in the subnet. The network router will use the last
usable IP address in the subnet.
Step 2: Write down the IP address information for each device.
Device IP address Mask Gateway
Host1 192.168.7.1 255.255.255.128 192.168.7.126
Router1-Fa0/0 192.168.7.126 255.255.255.128 -------------
Host2 192.168.7.129 255.255.255.192 192.168.7.190
Router1-Fa0/1 192.168.7.190 255.255.255.192 -------------
Table 1. IP Address Assignments
Before proceeding, verify your IP addresses with the instructor

1 comment:

Unknown said...

thanks it has beenvery helpful

 

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